A bacteria population starts at 2,032 and decreases at about 15% per day...?

A bacteria population starts at 2,032 and decreases at about 15% per day. Write a function representing the number of bacteria present each day. After how many days will there be fewer than 321 bacteria? Please help me!!!

A bacteria population starts at 2,032 and decreases at about 15% per day...?
321=2032*.85^n


log (321/2032)/log(.85)=n


n=11.35 days
Reply:f(x)=2032 * 0.85^x





where x = the number of days.





Then, try different values for x (increasing) until you get f(x) is less than 321.





The answer is after 12 days.